Question

30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentration of the Ca(OH)^2 solution in mol/dm^3 and g/dm^3

Answer 1

d

Step-by-step explanation:

d

Answer 2

Answer: Thus concentration of
`Ca(OH)_2` in
`mol/dm^3` is 0.011 and in
`g/dm^3` is 0.814

Step-by-step explanation:

To calculate the concentration of
`Ca(OH)_2`, we use the equation given by neutralization reaction:

`n_1M_1V_1=n_2M_2V_2`

where,

`n_1,M_1\text{ and }V_1` are the n-factor, molarity and volume of acid which is
`HCl`

`n_2,M_2\text{ and }V_2` are the n-factor, molarity and volume of base which is
`Ca(OH)_2`

We are given:

`n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3`
`1cm^3=0.001dm^3`

Putting values in above equation, we get:

`1* 0.06mol/dm^3* 0.011dm^3=2* M_2* 0.030dm^3\\\\M_2=0.011mol/dm^3`

The concentration in
`g/dm^3` is
`0.011mol/dm^3* 74g/mol=0.814g/dm^3`

Thus concentration of
`Ca(OH)_2` is
`0.011mol/dm^3` and
`0.814g/dm^3`