143k views
2 votes
Write the equation of a circle with a center at (-2, 1) and passes through
the point (0, 2). ​

User Marta
by
5.1k points

1 Answer

2 votes

Answer:


(x+2)^2} +(y-1)^2}=5

Explanation:


(x-h)^2} +(y-k)^2}=r^2

r=
√(5)

h=-2

k=1

Plug in


(x+2)^2} +(y-1)^2}=5

User Juel
by
5.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.