Question

The perimeter of a rectangle is 141 feet, and the length is twice the width. What are the dimensions ?

Answer 1

`\boxed{Width = 23.5 \ feet}`

`\boxed{Length = 47 \ feet}`

Explanation:

Let Length be l and Width be w

Perimeter = 2(Length) + 2(Width)

Condition # 1:

2l+2w = P

=> 2 l + 2 w = 141

Condition # 2:

=> l = 2w

Putting the second equation in the first one

=> 2(2w)+2w = 141

=> 4w + 2w = 141

=> 6w = 141

Dividing both sides by 6

=> Width = 23.5 feet

Given that

=> l = 2w

=> l = 2(23.5)

=> Length = 47 feet

Answer 2

The width is 23.5 ft and the length is 47 ft

Explanation:

The perimeter of a rectangle is given by

P = 2(l+w)

141 = 2(l+w)

The length is twice the width

l = 2w

141 = 2 ( 2w+w)

141 = 2( 3w)

141 = 6w

Divide each side by 6

141/6 = 6w/6

23.5 = w

l = 2w = 2(23.5) = 47

The width is 23.5 ft and the length is 47 ft