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If d varies directly as T^2 and D equals 192 when t equals 8 find d when T equals 2

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Answer:

d = 12

Explanation:


d \alpha T^2 \\d = kT^2.....(1)\\192 =8^2k\\192=64k\\(192)/(64) =(64k)/(64) \\k = 3\\d =3T^2 = Formula\: connecting\: d \:and\: T\\\\d = 3(2)^2\\d = 3(4)\\d =12

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