Question

if you vertically stretch the expontial function f(x) = 2^2 by a factor of 5, what is the equation of the new function?

Answer 1

g(x) =
`5(2^(2x) )`

Explanation:

If a function f(x) is vertically stretched by a factor of k, the new function we get in the form of k.f(x).

Rule to be followed,

y = k.f(x)

Where k > 1

If the function is vertically compressed then 0 < k < 1

Following the same rule,

A function, f(x) =
`2^(2x)` when vertically stretched by a factor of 5,

Transformed function will be,

g(x) =
`5(2^(2x) )`