Question

Calculating heat gained, need help!!!

Q=(m)(c)(triangle T)

trial 1:

Q=(0.4)(4.186 J/kg)(78)=?

trial 2:

Q=(0.6)(4.186 J/kg)(78)=?

trial 3:

Q=(0.45)(4.186 J/kg)(75)=?

Answer 1

Step-by-step explanation:

q = mCΔT

where m is mass,

C is specific heat capacity,

and ΔT is change in temperature.

Make sure all your units match. Assuming the substance is water, C = 4186 J/kg/°C.

Trial 1:

q = (0.4 kg) (4186 J/kg/°C) (78°C)

q = 130,600 J

Trial 2:

q = (0.6 kg) (4186 J/kg/°C) (78°C)

q = 195,900 J

Trial 3:

q = (0.45 kg) (4186 J/kg/°C) (75°C)

q = 141,300 J