10.0k views
4 votes
What is the factorization of 2x^2+28+98

User Mtrakal
by
8.8k points

1 Answer

4 votes

Answer:


2(x^2+63)

Step 1:

To solve this, we have to add the terms without any variables together.


2x^2+28+98\\2x^2+126

Step 2:

To factor this, we have to find the multiples of 2x^2 and 126.


2x^2 = 2x, x\\126 = 63, 2

Now, we can factor these numbers like this:


2(x^2+63)

When we multiply the numbers, we get 2x^2 + 126, and when we separate 126, we get our original question, so that means our factoring is correct.

User Malaverdiere
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.