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Find the sum of all solutions to $(4x+3)(x-8)+(x-1)(4x+3)=0$

User Rubal
by
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1 Answer

2 votes

Answer:

3 3/4

Explanation:

(4x+3)(x-8)+(x-1)(4x+3)=0

Factor out 4x+3

(4x+3)( x-8+x-1) =0

Combine terms

(4x+3) ( 2x-9) =0

Using the zero product property

4x+3 = 0 2x-9 =0

4x=-3 2x = 9

x = -3/4 x = 9/2

Sum the solutions

-3/4 + 9/2

-3/4 + 18/4

15/4

3 3/4

User Satya V
by
6.1k points