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O A. lw= (x - 5)(x - 5); 49 square feet

O B. /w = x(x - 5); 84 square feet
O c. /w = (x + 5)(x + 5); 289 square feet
D. lw= (x + 5)(x - 5); 119 square feet

O A. lw= (x - 5)(x - 5); 49 square feet O B. /w = x(x - 5); 84 square feet O c. /w-example-1
User Jagatjyoti
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1 Answer

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Answer:

D.
lw = (x + 5)(x - 5) ; 119 ft^2

Explanation:

Dimensions of the old square brick patio:


length (l) = x ft


width (l) = x ft

Note: a square has equal side measure

Dimensions of the new patio


length (l) = (x + 5) ft ==> she increased length by 5 ft


width (l) = (x - 5) ft she reduced width by 5 ft

Expression of the length and width of the new patio is:
lw = (x + 5)(x - 5)

Area of the new patio:

Dimension of original patio = x by x = 12 ft by 12 ft.

To find area of the new patio, replace x with 12 in the expression,
lw = (x + 5)(x - 5) , which gives you the area.


area = lw = (12 + 5)(12 - 5)


area = (17)(7)


area = 199 ft^2

Answer is D.
lw = (x + 5)(x - 5) ; 119 ft^2