Question

Solve 3x^2-4x-1=0 using quadratic form.

Answer 1

Here is your answer!!!

Explanation:

a=3,b=-4,c=-1

Discriminate (D)= b^2-4ac

D= (-4)^2-4(3)(-1)

D=16-(12)

D=16-12=4

x=-b±√b^2-4ac/2a

x=-(-4)±√4/2(3)

x=4±2/6

x=4+2/6=1

x=4-2/6=1/3

x=1,1/3