Answer:
![(x^2-9)/(x-3)= \Large \boxed{x+3}](https://img.qammunity.org/2021/formulas/mathematics/college/7uhsrins8vi2cmxtlq3sfu0ed1hly2ril9.png)
Explanation:
Hello,
We need to work a little bit of the expression to see if we can simplify.
Do you remember this formula?
for any a and b reals, we can write
![a^2-b^2=(a-b)(a+b)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ccqa9hgeork2so6kgz7f4se8ay36tabd90.png)
We will apply it.
For any x real number different from 3 (as dividing by 0 is not allowed)
![(x^2-9)/(x-3)=(x^2-3^2)/(x-3)=((x-3)(x+3))/(x-3)=x+3](https://img.qammunity.org/2021/formulas/mathematics/college/7r1hvq50ilmv3u4dusgdb68mvzds6ia38k.png)
So the winner is C !!
Hope this helps.
Do not hesitate if you need further explanation.
Thank you