Question

HELP ASAPPP ITS TIMED

Given that sin thata= 21/29, what is the value of cos thata, for 0°<thata<90°?
a- sqrt 20/29
b -20/29
c 20/20
d sqrt 20/29​

Answer 1

The value of cos theta for 0° < theta < 90° will be 20 / 29

Explanation:

To solve this problem we can express three trig functions as ratios involving the sides of a right-angle triangle, the adjacent side, the opposite side and the hypotenuse. In this case sin θ = a / c, such that a = 21 and c = 29.

By Pythagorean Theorem,

`b = √(c^2-a^2) = √(29^2-21^2) = √(841-441) = √(400) = 20`

Therefore cos θ = b / c = 20 / 29. This is the cosine ration of the adjacent side over the hypotenuse.