Question

ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Explanation:

We have f(x) and g(x). We are to evaluate each of these functions at the domain values given (1, 2, 3, 4, 5, and 6) and see where the output is the same.

`f(1)=-(1)^2+4(1)+12` and f(1) = 15

`f(2)=-(2)^2+4(2)+12` and f(2) = 16

`f(3)=-(3)^2+4(3)+12` and f(3) = 15

`f(4)=-(4)^2+4(4)+12` and f(4) = 12

`f(5)=-(5)^2+4(5)+12` and f(5) = 7

`f(6)=-(6)^2+4(6)+12` and f(6) = 0

Now for g(x) at each of these domain values:

g(1) = 1 + 2 and g(1) = 3

g(2) = 2 + 2 and g(2) = 4

g(3) = 3 + 2 and g(3) = 5

g(4) = 4 = 2 and g(4) = 6

g(5) = 5 + 2 and g(5) = 7

g(6) = 6 + 2 and g(6) = 8

It looks like the outputs are the same at f(5) and g(5). Actually, the domains are the same as well! f(5) = g(5)