Question

If a boy (m = 50kg) at rest on skates is pushed by another boy who exerts a force of 200 N on him and if the first boy's final velocity is 8 m/s, what was the contact time? t= s

Answer 1

t=2 s

Step-by-step explanation:

Answer 2

t = 2 seconds

Step-by-step explanation:

It is given that,

Mass of a boy, m = 50 kg

Initial speed of boy, u = 0

Final speed of boy, v = 8 m/s

Force exerting by another boy, F = 200 N

Let t is the time of contact. The force acting on an object is given by :

F = ma

a is acceleration

So,

`F=(m(v-u))/(t)\\\\t=(m(v-u))/(F)\\\\t=(50* 8)/(200)\\\\t=2\ s`

So, the contact time is 2 seconds.