Question

Can someone help fast please

Answer 1

`(3a)/(a-2)`

Explanation:

`(2a - 7)/(a)*(3a^2)/(2a^2 - 11a + 14)`

Factorise
`2a^2 - 11a + 14}`

`(2a - 7)/(a)*(3a^2)/((2a - 7)(a - 2))`

`2a - 7` cancels 2a - 7

`(1)/(a)*(3a^2)/((1))(a - 2))`

`(1(3a^2))/(a(a-2))`

`(a(3a))/(a(a-2))`

"a" cancels "a"

`(3a)/(a-2)`

Thus,

`(2a - 7)/(a)*(3a^2)/(2a^2 - 11a + 14)` =
`(3a)/(a-2)`