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Find the critical numbers for f(x)=cos(x)+sin^2(x) on the interval [0,2pi]

1 Answer

3 votes

Answer:

Explanation:

Rad [0,2
\pi]

f(x)=cos(x)+sin²(x)=cos(x)+1-cos²(x)

--[cos(x)-1/2]²+5/4=f(x)

when cos(x)=1/2,the f(x) has Max=5/4

cos(x)=1/2,x=
\pi/3(Rad) or 60°(Deg)

User Lorenz Henk
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