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Jacob and issac decided to run to the basketball court after school the basketball court is 5 1/4 Miles from school the boys run at a pace 3 3/8 miles per hour

1 Answer

1 vote

Answer:
1(5)/(9)\text{ minutes}

Explanation:

Complete question is provided in the attachment below.

Given: Jacob and Issac decided to run to the basketball court

Distance between basketball court and school =
5(1)/(4) miles


=(21)/(4) miles

Speed =
3(3)/(8) miles per hour


=(27)/(8) miles per hour

Since, time = (distance) ÷ ( speed)

Now, the time taken by boys to arrive at the basketball court =
(21)/(4)/(27)/(8) hours


=(21)/(4)*(8)/(27)\\\\=(7*2)/(9)=(14)/(9)\\\\=1(5)/(9)\text{ minutes}

Hence, the required length of time =
1(5)/(9)\text{ minutes}

Jacob and issac decided to run to the basketball court after school the basketball-example-1
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