The given question is incomplete. The complete question is :
A chemist prepares a solution of barium acetate by measuring out 32 g of barium acetate into a 350 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's barium acetate solution. Round your answer to significant digits.
Answer: The concentration of barium acetate solution is 0.375 mol/L
Step-by-step explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
![Molarity=(n* 1000)/(V_s)](https://img.qammunity.org/2021/formulas/chemistry/college/o6z9apkd0ml88ittegxnu80ge0mv0l6o3t.png)
where,
n = moles of solute
= volume of solution in ml
moles of
=
![\frac{\text {given mass}}{\text {Molar mass}}=(32g)/(255g/mol)=0.125mol](https://img.qammunity.org/2021/formulas/chemistry/college/zfluuet94kfsh4mlx2onp0yfifp64ngcw7.png)
Now put all the given values in the formula of molality, we get
![Molarity=(0.125* 1000)/(350ml)](https://img.qammunity.org/2021/formulas/chemistry/college/pg22tftnwcz9c8vt3lhgwbxcea2d6sxllj.png)
![Molarity=0.357M](https://img.qammunity.org/2021/formulas/chemistry/college/pl6owqcrrv6gfu7hqqsw96fvmqkkbdnovb.png)
Therefore, the concentration of solution is 0.375 mol/L