Question

1. Two TCP entities communicate across a reliable network. Let the normalized time to transmit a fixed length segment equal 1. Assume that the end-to-end propagation delay is 3 and that it takes 2 to deliver data from a received segment to the transport user. The receiver initially grants a credit of 7 segments. The receiver uses a conservative flow control policy and updates its credit allocation at every opportunity. What is the maximum achievable throughput

Answer 1

The answer is "0.77"

Step-by-step explanation:

The fixed-length segment value = 1

The propagation time of one end to another end is = 3

The Transfer power to move the consumer from the obtained segment = 2

The second last sender assigns a loan = 7 segments

The overall transmission time = 3+2+3 = 8

The maximum throughput value is:

`\to (7)/((1 + 8))\\\\ \to (7)/(9)\\\\\to 0.77`