Answer:
see below
Explanation:
The equation of the hyperbola can be written as ...
((x -h)/a)² -((y -k)/b)² = 1
This has asymptotes ...
(x -h)/a ± (y -k)/b = 0
Solving for y, we have ...
y = ±(b/a)(x -h) +k
Filling in the given values a=6, b=8, h=1, k=2, we have ...
y = ±8/6(x -1) +2
![y=(\pm4x\mp4+6)/(3)\\\\\boxed{y=(4x+2)/(3)\ \text{and }y=(10-4x)/(3)}](https://img.qammunity.org/2021/formulas/mathematics/college/zcsudody98ycni9t20nrfuq6ay77mn4kgc.png)