Question

The nonreflective coating on a camera lens with an index of refraction of 1.21 is designed to minimize the reflection of 570-nm light. If the lens glass has an index of refraction of 1.52, what is the minimum thickness of the coating that will accomplish this ta

Answer 1

Answer: 117.8 nm

Step-by-step explanation:

Given,

Nonreflective coating refractive index : n = 1.21

Index of refraction:
`n_0` = 1.52

Wave length of light = λ = 570 nm =
`570*10^(-9)\ m`

`\text{ Thickness}=(\lambda)/(4n)`

`=(570*10^(-9)\ m)/(4*1.21)\\\\\approx(117.8* 10^(-9)\ m)/(1)\\\\=117.8\text{ nm}`

Hence, the minimum thickness of the coating that will accomplish= 117.8 nm