148k views
5 votes
The Department of Education would like to test the hypothesis that the average debt load of graduating students with a bachelor's degree is equal to $17,600. A random sample of 28 students had an average debt load of $18,800. It is believed that the population standard deviation for student debt load is $4800. The α is set to 0.05. The confidence interval for this hypothesis test would be ________.

User Whusterj
by
5.3k points

1 Answer

7 votes

Answer:

A 95% confidence interval for the population average debt load of graduating students with a bachelor's degree is [$17,022.05, $20,577.94].

Explanation:

We are given that a random sample of 28 students had an average debt load of $18,800. It is believed that the population standard deviation for student debt load is $4800. The α is set to 0.05.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. =
(\bar X-\mu)/((\sigma)/(√(n) ) ) ~ N(0,1)

where,
\bar X = sample average debt load = $18,800


\sigma = population standard deviation = $4,800

n = sample of students = 28


\mu = population average debt load

Here for constructing a 95% confidence interval we have used a One-sample z-test statistics because we know about population standard deviation.

So, 95% confidence interval for the population mean,
\mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 5% level of

significance are -1.96 & 1.96}

P(-1.96 <
(\bar X-\mu)/((\sigma)/(√(n) ) ) < 1.96) = 0.95

P(
-1.96 * {(\sigma)/(√(n) ) } <
{\bar X-\mu} <
1.96 * {(\sigma)/(√(n) ) } ) = 0.95

P(
\bar X-1.96 * {(\sigma)/(√(n) ) } <
\mu <
\bar X+1.96 * {(\sigma)/(√(n) ) } ) = 0.95

95% confidence interval for
\mu = [
\bar X-1.96 * {(\sigma)/(√(n) ) } ,
\bar X+1.96 * {(\sigma)/(√(n) ) } ]

= [
\$18,800-1.96 * {(\$4,800)/(√(28) ) } ,
\$18,800+1.96 * {(\$4,800)/(√(28) ) } ]

= [$17,022.05, $20,577.94]

Therefore, a 95% confidence interval for the population average debt load of graduating students with a bachelor's degree is [$17,022.05, $20,577.94].

User Taylorthurlow
by
5.4k points