Answer:
Use a ratio of 0.44 mol lactate to 1 mol of lactic acid
Step-by-step explanation:
John could prepare a lactate buffer.
He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.
![\text{pH} = \text{pK}_{\text{a}} + \log\frac{\text{[A$^(-)$]}}{\text{[HA]}}\\\\3.5 = 3.86 + \log\frac{\text{[A$^(-)$]}}{\text{[HA]}}\\\\\log\frac{\text{[A$^(-)$]}}{\text{[HA]}} = 3.5 - 3.86 = -0.36\\\\\frac{\text{[A$^(-)$]}}{\text{[HA]}} = 10^(-0.36) = \mathbf{0.44}](https://img.qammunity.org/2021/formulas/chemistry/college/z14i2f2j3yu0vsoqka6qkvhnd9h3rsmu4o.png)
He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.
For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.