Question

Calculate the entropy change for the reaction: HCl(g) + NH3(g) -> NH4Cl(s) Entropy data: HCl: 187 J/K mol NH3: 193 J/K mol NH4Cl: 94.6 J/K mol

Answer 1

-198.3 J/K mol

Step-by-step explanation:

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Answer 2

-285.4 J/K

Step-by-step explanation:

Let's consider the following balanced equation.

HCl(g) + NH₃(g) ⇒ NH₄Cl(s)

We can calculate the standard entropy change for the reaction (ΔS°r) using the following expression.

ΔS°r = 1 mol × S°(NH₄Cl(s)) - 1 mol × S°(HCl(g)) - 1 mol × S°(NH₃(g))

ΔS°r = 1 mol × 94.6 J/K.mol - 1 mol × 187 J/K.mol - 1 mol × 193 J/K.mol

ΔS°r = -285.4 J/K