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How do I simplify this (sinx)/(secx+1)

User Not Amused
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1 Answer

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Answer:

Explanation:


(sin~x)/(sec~x+1) =(sin~x)/((1)/(cos~x)+1 ) =(sin~x~cos~x)/(1+cos~x) \\=(sin~x~cos~x)/(1+cos~x) * (1-cos~x)/(1-cos~x) \\=(sin~x~cos~x(1-cos~x))/(1-cos^2 x) \\=(sin~x~cos~x(1-cos~x))/(sin^2x) \\=(cos~x(1-cos~x))/(sin~x) \\=cos ~x(csc~x-cot~x)\\or\\=cot~x(1-cos~x)

User NoAngel
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