Question

What is the solution to the system of equations below? HELP!!!! y = negative one-fourth x + 2 and 3 y = negative three-fourths x minus 6 no solution infinitely many solutions (–16, 6) (–16, –2)

Answer 1

No solution

Explanation:

y = -1/4x + 2

3y = -3/4x - 6

Plug y as -1/4x + 2 in the second equation.

3(-1/4x + 2) = -3/4x - 6

-3/4x + 6 = -3/4x - 6

-3/4x + 3/4x = -6 -6

0 = -12

No solution.

Answer 2

No solution

Explanation:

Step 1: Write out equations

y = -1/4x + 2

3y = -3/4x - 6

Step 2: Substitution

3(-1/4x + 2) = -3/4x - 6

Step 3: Distribute

-3/4x + 6 = -3/4x - 6

From here, we can see that we have the same slope but different y-intercept. This means that the 2 lines are parallel and therefore never intersect.

Alternatively, you could graph the equations and see that the 2 lines are parallel and never intersect.