Question

A 5000 kg mass rocket “breaks the engine” when it is 100 m high and climbing at a speed of 75 m / s. Calculate:

1) The maximum height it will reach
2) The speed with which it will hit the ground after the fall.

Answer 1

1:281.25m

2:75m/s

Step-by-step explanation:

using the equation

`v^(2) = u^(2) + 2gs`

at maximum height v is zero so using that you can make s the subject of the formula

`h \: max = u^(2) / \: 2g`

so substitute the velocity 75 and the constant g-10m/s^2

as for the returning velocity we say displacement is zero since you go and come back the same distance

so

`v = { + or - }u`

u is the initial speed in this case it's positive since going in the direction of gravity