Answer:
-- Cone
-- Cylinder
-- Sphere
Best Buy: Sphere Clay
Explanation:
Given
Solid Shapes: Cone, Cylinder, Sphere
Cost of Cone Clay = $12
Cost of Cylinder Clay = $30
Cost of Sphere Clay = $28
Required
Determine the volume of each shape
Which is the best buy
CONE
Calculating Volume
The volume of a cone is calculated as thus;
![Volume = (1)/(3)\pi r^2h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1dbfmkd963zfyuhg93tmx8290sel30v17r.png)
From the attached diagram
Radius, r = 9 inches; Height, h = 12 inches and
![\pi = 3.14](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y04rzsjmfedht1b41g0s1en1rzhn5jx8g3.png)
Substitute these values in the above formula;
![Volume = (1)/(3) * 3.14 * 9^2 * 12](https://img.qammunity.org/2021/formulas/mathematics/high-school/paoyyol3iye56qveyp4x2funbsaa7jvtfm.png)
![Volume = (3052.08)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ucp53zqw3rhn4d0y28wsb1pi2b9y3bbtxr.png)
![Volume = 1017.36\ in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/x6cormbqw9ro4pbwunhhszb0v7ck39ffth.png)
Calculating Volume:Price Ratio
The unit cost of the cone is calculated as thus;
![Volume:Price = (Volume)/(Total\ Cost)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4p7tw5ba6mpu4xrocfhpxvhv3jywc6v4rq.png)
Where
![Volume = 1017.36\ in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/x6cormbqw9ro4pbwunhhszb0v7ck39ffth.png)
(Given)
![Volume:Price = (1017.36\ in^3)/(\$ 12)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9md3qoeykbnv5uw0k7oaxpyhvdhzbhfjid.png)
![Volume:Price = 84.78 in^3/\$](https://img.qammunity.org/2021/formulas/mathematics/high-school/a58u7i18wd2wxtflg3awa2jx8u6wksxz6m.png)
![Volume:Price = 84.78 in^3:\$1](https://img.qammunity.org/2021/formulas/mathematics/high-school/89z5jj3mhlr4in74v6ao6zczghd2urx802.png)
CYLINDER
Calculating Volume
The volume of a cylinder is calculated as thus;
![Volume = \pi r^2h](https://img.qammunity.org/2021/formulas/mathematics/high-school/j3yk2zftg09xjs5havgxb81maf59lj8iah.png)
From the attached diagram
Radius, r = 9 inches; Height, h = 12 inches and
![\pi = 3.14](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y04rzsjmfedht1b41g0s1en1rzhn5jx8g3.png)
Substitute these values in the above formula;
![Volume = 3.14 * 9^2 * 12](https://img.qammunity.org/2021/formulas/mathematics/high-school/m9bxzr323801dxmlxc3imnt0gq83zfvlkm.png)
![Volume = 3052.08\ in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/6nki1yyh20f450pt7j47deeukhhejl5rtb.png)
Calculating Volume:Price Ratio
The unit cost of the cone is calculated as thus;
![Volume:Price = (Volume)/(Total\ Cost)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4p7tw5ba6mpu4xrocfhpxvhv3jywc6v4rq.png)
Where
![Volume = 3052.08\ in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/6nki1yyh20f450pt7j47deeukhhejl5rtb.png)
(Given)
![Volume:Price = (3052.08\ in^3)/(\$ 30)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yipxi171i0dztjwothknwbhlhf0ax2d6m0.png)
![Volume:Price = 101.736\ in^3/\$](https://img.qammunity.org/2021/formulas/mathematics/high-school/zqj12n778rkg6p2cyxuizzhjfmv0v5bulk.png)
![Volume:Price = 101.736\ in^3:\$1](https://img.qammunity.org/2021/formulas/mathematics/high-school/y6i8is6gxtncko36a6lj4jow9lx7dsi6ux.png)
SPHERE
Calculating Volume
The volume of a sphereis calculated as thus;
![Volume = (4)/(3)\pi r^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/5c610f79i160zop0uy502xfxfijkf4hg2a.png)
From the attached diagram
Radius, r = 9 inches; and
![\pi = 3.14](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y04rzsjmfedht1b41g0s1en1rzhn5jx8g3.png)
Substitute these values in the above formula;
![Volume = (4)/(3) * 3.14 * 9^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/tg1cyuiuhivi4272bz49doyb6gmsfb8quw.png)
![Volume = (9156.24)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/f7vct56s60tx96kal1nemz06cfnswz4ij0.png)
![Volume = 3052.08\ in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/6nki1yyh20f450pt7j47deeukhhejl5rtb.png)
Calculating Volume-Price ratio
The unit cost of the cone is calculated as thus;
![Volume:Price = (Volume)/(Total\ Cost)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4p7tw5ba6mpu4xrocfhpxvhv3jywc6v4rq.png)
Where
![Volume = 3052.08\ in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/6nki1yyh20f450pt7j47deeukhhejl5rtb.png)
(Given)
![Volume:Price = (3052.08\ in^3)/(\$ 28)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qhq6h9nw65faa0e7n8not67f7e6tezm07x.png)
![Volume:Price = 109.003\ in^3/\$](https://img.qammunity.org/2021/formulas/mathematics/high-school/x4x98cse064t6p1utv2pz1y8ugskdr0wpy.png)
![Volume:Price = 109.003\ in^3:\$1](https://img.qammunity.org/2021/formulas/mathematics/high-school/x2uyjzw1g2w1ncs15jn4giwfop4i8gjng5.png)
Comparing the Volume:Price ratio of the three clay;
The best buy is the sphere because it has the highest volume:price ratio.
Having the highest volume:price ratio means that with $1, one can get more clay from the sphere compared to other types of clay