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Find the H+ and (OH)- concentrations in 0.01M KOH

User Inmyth
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Answer:

Step-by-step explanation:

KOH will split as follows

KOH ⇄ K⁺ + OH⁻

KOH is a strong base so it will split 100 %

.01 M .01 .01

concentration of OH⁻ = .01 gm ion / litre

[ OH⁻ ] = .01 = 10⁻² M

[ H⁺ ] [ OH⁻ ] = 10⁻¹⁴

[ H⁺ ] x 10⁻² = 10⁻¹⁴

[ H⁺ ] = 10⁻¹² M .

User Mohit Gupta
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