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How many moles of sodium ions are in 5.70 grams of sodium sulfide?

User Niel
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2 Answers

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19 votes

Final answer:

To find the number of moles of sodium ions in 5.70 grams of sodium sulfide, calculate the moles of sodium sulfide and then multiply by the number of sodium ions per mole of sodium sulfide.

Step-by-step explanation:

To determine the number of moles of sodium ions in 5.70 grams of sodium sulfide, we need to consider the formula of sodium sulfide (Na2S). In this compound, there are two sodium ions (Na+) for every molecule of sodium sulfide. So, we can calculate the moles of sodium ions by multiplying the moles of sodium sulfide by the number of sodium ions per mole of sodium sulfide.

First, we need to determine the molar mass of sodium sulfide. The molar mass of Na2S is calculated as follows:

Molar mass = (2 x molar mass of Na) + (1 x molar mass of S)

By consulting a periodic table, we find that the molar mass of Na is approximately 22.99 g/mol and the molar mass of S is approximately 32.07 g/mol.

So, the molar mass of Na2S is (2 x 22.99 g/mol) + (32.07 g/mol) = 87.05 g/mol.

Now, we can calculate the moles of sodium sulfide:

moles = mass / molar mass = 5.70 g / 87.05 g/mol = 0.0656 mol

Since there are 2 sodium ions in each mole of sodium sulfide, the number of moles of sodium ions will be:

moles of sodium ions = 2 x moles of sodium sulfide = 2 x 0.0656 mol = 0.1312 mol

User Raeven
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29 votes
29 votes

Answer:

0.07

Step-by-step explanation:

to find mole you divide mass by the relative atomic mass

Now you find the relative atomic of of moles pf he number sodium sulfide

then you thequation for finding moles to find mole of sodium

User BengtBe
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