Answer:
![\mathrm{1.086 \: g/cm^3 }](https://img.qammunity.org/2021/formulas/physics/high-school/2avovguofkcb0ut5vb51lc8t5yjc648sus.png)
Step-by-step explanation:
Volume of fresh water ⇒ 1600 cm³
Density of fresh water ⇒ 1 g/cm³
Volume of sea water ⇒ 1200 cm³
Density of sea water ⇒ 1.2 g/cm³
![density=(mass)/(volume)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/3ohvsxn3wm7o8ow2l8arn8y2amacvdm776.png)
![mass=density * volume](https://img.qammunity.org/2021/formulas/physics/high-school/vbpzzwqwi1a8z7odukssuvxvebor31aigl.png)
Calculate mass of fresh water.
![m=1600 * 1](https://img.qammunity.org/2021/formulas/physics/high-school/3k450iqpqbbiwprlpi88hxvln1im92msnc.png)
![m=1600 \: g](https://img.qammunity.org/2021/formulas/physics/high-school/n693s8iesl0t4vs8ietlbp80zh6d24s5q9.png)
Calculate the mass of sea water.
![m=1200 * 1.2](https://img.qammunity.org/2021/formulas/physics/high-school/9cufe6126ked2tos37l1g5j4nornmeicen.png)
![m=1440 \: g](https://img.qammunity.org/2021/formulas/physics/high-school/2neg5m1vpx92pftli0tey3g60k3ld4bxdo.png)
Find the density of the mixture.
![density=(mass)/(volume)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/3ohvsxn3wm7o8ow2l8arn8y2amacvdm776.png)
![\rho = (1600+1440)/(1600 + 1200)](https://img.qammunity.org/2021/formulas/physics/high-school/1i998ibe96s0t0shlunu0o9ifpczpkckeg.png)
![\rho = (3040)/(2800)](https://img.qammunity.org/2021/formulas/physics/high-school/ije4k6itt89ujnkyfvmvk62dah50bgtsiv.png)
![\rho= 1.0857...](https://img.qammunity.org/2021/formulas/physics/high-school/gsir9zv9b7n3t6bqfdskjakfheiondrke9.png)