Question

Need help with this question ​

Answer 1

`- 2 {x}^(5) {y}^(7)`

Solution:

`- 2 {x}^(3) {y}^(4) {x}^(2) {y}^(3)`

`= 2 {x}^((3 + 2)) {y}^((4 + 3))`

`= - 2 {x}^(5) {y}^(7)`

`{\boxed{\blue{\textsf{Some Important Laws of Indices}}}}`

`{a}^(n).{a}^(m)={a}^((n + m))`

`{a}^(-1)=(1)/(a)`

`\frac{{a}^(n)}{ {a}^(m)}={a}^((n-m))`

`{({a}^(c))}^(b)={a}^(b* c)={a}^(bc)`

`{a}^{(1)/(x)}=\sqrt[x]{a}`

`a^0 = 1`

`[\text{Where all variables are real and greater than 0}]`

Answer 2

`- 2 {x}^(5) {y}^(7)`

Last option is correct.

Explanation:

`- 2 {x}^(3) {y}^(4) {x}^(2) {y}^(3)`

Multiply the terms with the same base by adding their exponents

`- 2 {x}^(3 + 2) {y}^(4 + 3)`

Add the numbers

`- 2 {x}^(5) {y}^(7)`

Hope this helps..

Best regards!