Question

A load of 500N is carried by 200N effort in a simple machine having load distance 3m Calculate effort distance.​

Answer 1

2.5 m

Step-by-step explanation:

Load ( L ) = 500 N

Effort ( E ) = 200 N

Load distance ( LD ) = 3 m

Effort distance ( ED ) = ?

Now, Let's find the Effort distance ( ED )

We know that,

Output work = Input work

i.e L × LD = E × ED

plug the values

`500 * 3 = 200 * </strong><strong>ED</strong><strong>`

multiply the numbers

`1500 = 200 * </strong><strong>ED</strong><strong>`

Swipe the sides of the equation

`200 \: </strong><strong>ED</strong><strong> \: = 500`

Divide both sides of the equation by 200

`(200 \: </strong><strong>ED</strong><strong>)/(200) = (500)/(200)`

Calculate

`</strong><strong>ED</strong><strong>\: = 2.5 \: m`

Hope this helps..

best regards!!