Question

Fins the zeroes of the quadratic equation : 4√ 5 x^ 2 - 24x - 9√ 5

10th grade Cbse chapter 2 : Polynomials

pls give the step by step explanation so that i can understand​

Answer 1

Explanation:

Hello,

First of all, we know that the solution of the following equation

`ax^2+bx+c=0`

are

`(-b\pm√(b^2-4ac))/(2a) \ \text{ when } \Delta=b^2-4ac \geq 0`

I would suggest that you try to apply this formula first and check the solution only after you try.

Let's apply it in this case, we have:

`a=4√(5) \\ \\ b=-24 \\ \\ c= -9√(5)`

`\Delta=b^2-4ac=24^2+4*9*5=1296 \\ \\ √(\Delta)=36 \ \text{ and the solutions are } \\ \\ \\ x_1=(24-36)/(8√(5))=(-12)/(8√(5))=\boxed{(-3)/(2√(5))} \\ \\x_2=(24+36)/(8√(5))=(60)/(8√(5))=\boxed{(15)/(2√(5))}`

Hope this helps.

Do not hesitate if you need further explanation.

Thank you