Question

4. A number m is such that when it is divided by 30, 36, and 45 the remainder is always 7,

find the smallest possible value of m
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Answer 1

187

Explanation:

A number m is such that when it is divided by 30, 36 and 45 the remainder is always 7.

We should first find the LCM of 30, 36 and 45

We get that the LCM of the three numbers is 280 (working attached).

So now;

`(180)/(30)` = 6

`(180)/(36)` = 5

`(180)/(45)` = 4

But we need a number that leaves a remainder of 7 so we add 7 to 180 to get; 180 + 7 = 187.