Question

The perimeter of the rectangle below is 132 units.

Answer 1

The answer is 29 unit.

Explanation:

Here,

given that,

DC (l) =4z+1

CD (b)=5z+2

perimeter (p)= 132

now,

perimeter of rectangle (p) is= 2(l+b)

or, 132 = 2×{(4z+1)+(5z+2)}

or, 132= 2×(9z+3)

or, 132= 18z+6

or, 18z=132-6

or, z=126/18

or, z= 7.

therefore, 4z+1=4×7+1=29

5z+2= 5×7+2=37.

As our question is about to find AB,

DC = AB. (as opposite side of rectangle is equal).

so, the valueof AB is 29unit.

Hope it helps...