115k views
1 vote
The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 yd, find its area

User Mindtonic
by
7.4k points

2 Answers

7 votes

Answer:

100yd²

Explanation:

length=4x

width=x

perimeter=2(l+w)

50=2(4x+x)

50=2(5x)=10x

50=10x

x=5yd

width=5yd

length=20yd

area=length×width

=20×5

=100yd²

User RandallShanePhD
by
7.6k points
1 vote

Answer:


\boxed{\red{100 \: \: {yd} ^(2)}}

Explanation:

width = x

length = 4x

so,

perimeter of a rectangle


p= 2(l + w) \\ 50yd = 2(4x + x) \\ 50yd= 2(5x) \\ 50yd= 10x \\ (50yd)/(10) = (10x)/(10) \\ x = 5 \: \: yd

So, in this rectangle,

width = 5 yd

length = 4x

= 4*5

= 20yd

Now, let's find the area of this rectangle


area = l * w \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 * 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 100 {yd}^(2)

User Florian Feldhaus
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories