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Beth says that the graph of g(x)=x-5+1 is a

Translation of 5 units to the left and 1 unit up of
F(x)=x
She continues to explain that the point (0,0) on the square root function would be translated to the point (-5,1) on the graph of g(x) is Beths description of the transformation correct? Explain

2 Answers

7 votes

Answer:

No, Beth is not correct. The function g(x) has an h value of 5 and a k value of 1. This would be a horizontal translation of the square root function of 5 units to the right, rather than the left. Beth was correct about the vertical translation of the square root function of 1 unit up. The point (0, 0) from the square root function would be translated to the point (5, 1) on the graph of g(x).

Explanation:

This came right from Edg

User Wuntee
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5.8k points
5 votes

Answer: No.

Explanation:

The graph of g(x) = x - 5 + 1 is a Translation of 5 units to the right not to the left and 1 unit up of F(x) = x

the point (0,0) on the square root function would be translated at the same value which will be to the point (5,1) on the graph of g(x)

Beths description of the transformation is therefore incorrect.

User Blankman
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6.0k points