Question

Line p conatians point (6,-5) and is perpendicular to line q. The equation for line q is y=3x+5. Write the equation for line p.

Also need the slow of line p

Answer 1

y + 5 = (1/3)(x - 6)

Explanation:

Line p is perpendicular to line q, and therefore the slope of line p is the negative reciprocal of the slope of line q: -1/3.

Starting with the point-slope formula y - k = m(x - h), we get

y + 5 = (1/3)(x - 6)