Answer:
![- 3x + y = - 7](https://img.qammunity.org/2021/formulas/mathematics/high-school/wco4e1ftpp1hxp1xewpgccef014u7bey2z.png)
Option C is the correct option.
Explanation:
A line passes through ( 2 , -1 ) and ( 4 , 5 )
The equation of line:
![(y - y1)/(x - x1) = (y2 - y1)/(x2 - x1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/i1g4qoqjeq4gcwlbz64cyra4wrnjekslhb.png)
Plug the values
![( y - ( - 1))/(x - 2) = (5 - ( - 1))/(4 - 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/tf5ex7w9j5pru628xr4lckv6j0otyi3h11.png)
When there is a ( - ) in front of an expression in parentheses, change the sign of each term in the expression
![(y + 1)/(x - 2) = (5 + 1)/(4 - 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/kqhabvnc73oskvqevrt6q6py28x8ob57g2.png)
Add the numbers
![(y + 1)/(x - 2) = (6)/(4 - 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yag6iqzlruurtkirr9du27cmllet9lpehp.png)
Subtract the numbers
![(y + 1)/(x - 2) = (6)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ofpos8d19zq9v62mhyefy8sdlau5lf82hg.png)
Reduce the numbers with 2
![(y + 1)/(x - 2) = 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/sb6whiolgo47q3soiz2c5sa1xwpgltfbak.png)
Apply cross product property
![3x - 6 = y + 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/evq2ngdepr5d6l6unhsjz2ubyg0m5kn2qe.png)
Move variable to L.H.S and change its sign
Similarly, Move constant to R.H.S and change its sign
![3x - y = 1 + 6](https://img.qammunity.org/2021/formulas/mathematics/high-school/hv9fe8jdpciozumauwtdh3k13z04086xwq.png)
Add the numbers
![3x - y = 7](https://img.qammunity.org/2021/formulas/mathematics/high-school/46v6q76st0nimhxmhw635c3io8i0i2nwj8.png)
![- 3x + y = - 7](https://img.qammunity.org/2021/formulas/mathematics/high-school/wco4e1ftpp1hxp1xewpgccef014u7bey2z.png)
Hope this helps...
Best regards!