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PLEASE HELP ASAPPPP!!!

Solve the right triangle given that mA =30°, mC = 90° and a = 15. Then round your result to ONE decimal place

PLEASE HELP ASAPPPP!!! Solve the right triangle given that mA =30°, mC = 90° and a-example-1
User Harpax
by
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1 Answer

3 votes

Answer:

m∠B = 60°

b = 26 units

c = 30 units

Explanation:

In a right triangle ACB,

By applying Sine rule,


\frac{\text{SinA}}{a}=\frac{\text{SinB}}{b}=(SinC)/(c)

m∠A = 30°, m∠C = 90°

m∠A + m∠B + m∠C = 180°

30° + m∠B + 90° = 180°

m∠B = 180° - 120°

m∠B = 60°

Therefore,
\frac{\text{Sin30}}{15}=\frac{\text{Sin90}}{c}=\frac{\text{Sin60}}{b}


(1)/(30)=\frac{\text{Sin90}}{c}=\frac{\text{Sin60}}{b}


(1)/(30) =(1)/(c)=((√(3))/(2))/(b)


(1)/(30)=(1)/(c)=(√(3))/(2b)


(1)/(30) =(1)/(c) c = 30 units


(1)/(30)=(√(3))/(2b)

b = 15√3

b = 25.98

b ≈ 26 units

User Willlma
by
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