Question

What is the diameter of the circle whose center is at (6, 0) and that passes through the point (2, -3)?

Answer 1

10

Explanation:

`\left(x-h\right)^(2)+\left(y-k\right)^(2)=r^2`

`\left(x-6\right)^(2)+\left(y-0\right)^(2)=r^2\\`

We used (2,-3)

`\left(2-6\right)^(2)+\left(-3-0\right)^(2)=25`

`r^2=25\\` , so
`r = 5`

But this one is asking for the diameter, and to find it. It's simply 2r.

2*5 = 10