Answer:
The voltage is
![E_(cell) = 0.944 \ V](https://img.qammunity.org/2021/formulas/chemistry/college/bpnft4rms3lzinm8wduxu8773kcbturldj.png)
Step-by-step explanation:
Generally the half reaction for Zn, Zn2 half-cell is mathematically represented as
⇔
(reference study academy)
and the electric potential for this is a constant value
![E_(zn ) = -0.7618 \ V](https://img.qammunity.org/2021/formulas/chemistry/college/3567ie3utbk7abprf7lk2uvzm9c3spz0ia.png)
Generally the half reaction for Al, Al3 half-cell is mathematically represented as
⇔
![Al_((s))](https://img.qammunity.org/2021/formulas/chemistry/college/jje9uk00kp1k1j8gow23lviho5opr46xvp.png)
and the electric potential for this is constant value
![E_(Al ) = -1.662 \ V](https://img.qammunity.org/2021/formulas/chemistry/college/apgowd5xgtaeuo23kkjejraf4b33s6u59w.png)
Therefore the cell potential for an electrochemical cell is mathematically represented as
![E_(cell) = E_(zn ) - E_(Al )](https://img.qammunity.org/2021/formulas/chemistry/college/kqwodrfhlbkjpp2swebi0kzkjpewp1kgdq.png)
substituting values
![E_(cell) = -0.718 - (-1.662)](https://img.qammunity.org/2021/formulas/chemistry/college/f6hr01gthhj9medfo8549qxvjvhdrln8n8.png)
![E_(cell) = 0.944 \ V](https://img.qammunity.org/2021/formulas/chemistry/college/bpnft4rms3lzinm8wduxu8773kcbturldj.png)