Answer:
Step-by-step explanation:
We shall find out volume of air at NTP or at 273 K and 10⁵ Pa ( 1 atm )
Let it be V₂
![(P_1V_1)/(T_1) =(P_2V_2)/(T_2)](https://img.qammunity.org/2021/formulas/chemistry/high-school/k2kmvvu6ujru5sxef2s47w39fov5hioxle.png)
![(2* 10^5* 5.68)/(394) =(10^5* V_2)/(273)](https://img.qammunity.org/2021/formulas/chemistry/college/3cnkztj3cebbbj5a0idkbm52ybh9fkwtvt.png)
V₂ = 7.87 litres
22.4 litres of any gas is equivalent to 1 mole
7.87 litres of air will be equivalent to
7.87 / 22.4 moles
= .35 moles .