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A string of mass 60.0 g and length 2.0 m is fixed at both ends and with 500 N in tension. a. If a wave is sent along this string, what will be the wave's speed? A second wave is sent in the string, what is the new speed of each of the two waves?

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Answer:

a

The speed of wave is
v_1 = 129.1 \ m/s

b

The new speed of the two waves is
v = 129.1 \ m/s

Step-by-step explanation:

From the question we are told that

The mass of the string is
m = 60 \ g = 60 *10^(-3) \ kg

The length is
l = 2.0 \ m

The tension is
T = 500 \ N

Now the velocity of the first wave is mathematically represented as


v_1 = \sqrt{ (T)/(\mu) }

Where
\mu is the linear density which is mathematically represented as


\mu = (m)/(l)

substituting values


\mu = ( 60 *10^(-3))/(2.0 )


\mu = 0.03\ kg/m

So


v_1 = \sqrt{ (500)/(0.03) }


v_1 = 129.1 \ m/s

Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )

User Pavel Zagalsky
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