Question

Determine the number of grams of NaHCO3 that are in one liter of a 2.1 M solution

Answer 1

`\text{Molarity,}~ S= 2.1~mol/L\\\\\text{Molar mas of}~ NaHCO_3, ~M=84~~ g/mol\\\\\text{Volume,}~~ V = 1 ~L\\\\\text{Mass,} ~w = ?`

`\text{ We know that,}\\\\~~~~~S = \frac{n}V\\\\\implies n = SV\\\\\implies (w)/(M) = SV\\\\\implies w = SVM\\\\\implies w= 2.1 * 1 * 84\\\\\implies w =176.4 ~ g`