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4 votes
Solve : 3x + 9 < 4(x-5) -x + 3 + 2x

User Supamaze
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1 Answer

5 votes

Answer:

x > 13

Step-by-step explanation: I tried to work it out well.

I Hope it helps:)


3x + 9 < 4(x-5) -x + 3 + 2x\\\mathrm{Group\:like\:terms}\\3x+9<-x+2x+4\left(x-5\right)+3\\\mathrm{Add\:similar\:elements:}\:-x+2x=x\\3x+9<x+4\left(x-5\right)+3\\Expand ; x+4\left(x-5\right)+3\\=x+4x-20+3\\=5x-17\\3x+9<5x-17\\\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\3x+9-9<5x-17-9\\Simplify\\3x<5x-26\\\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}\\3x-5x<5x-26-5x\mathrm{Simplify}\\-2x<-26\\


Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)\\\left(-2x\right)\left(-1\right)>\left(-26\right)\left(-1\right)\\Simplify\\2x>26\\\mathrm{Divide\:both\:sides\:by\:}2\\(2x)/(2)>(26)/(2)\\\\x>13

User Sergey Alaev
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5.3k points