Answer:
7.3%
Explanation:
Let M = Maths
E = English
P(M ∪ E) = P(M) + P(E) - P( M ∩ E)
From the question:
P(M ∪ E) = 35.7%
P(M) = 18%
P(E) = 24%
P( M ∩ E) = unknown
35.7% = 18% + 24% - P( M ∩ E)
35.7% = 42% - P( M ∩ E)
P( M ∩ E) = 42% - 35.7%
P( M ∩ E) = 7.3%
Therefore, the probability that a student who receives an A in Math course will also receive an A in English course is 7.3%.