Question

Help!! I have problem to solve this question​

Answer 1

Explanation:

`(x-1)/(2) =t\\(y-2)/(3) =t\\(z-3)/(4) =t\\so~eq.~of~line~L_(1)~is\\(x-1)/(2) =(y-2)/(3) =(z-3)/(4) \\its~d.r's~are~2,3,4\\again~(x-2)/(1) =s\\(y-4)/(2) =s\\(z+1)/(-4) =s\\so~eq. ~of~line~L_(2)~is\\(x-2)/(1) =(y-4)/(2) =(z+1)/(-4) \\its~d.r's ~are~1,2,-4\\let ~the ~d.r's~of~line~perpendicular~to~both~L_(1)~and~L_(2)~be~a,b,c,~then~\\2a+3b+4c=0\\1a+2b-4c=0\\solving\\(a)/(3*-4-4*2) =(b)/(4*1-2*-4) =(c)/(2*2-3*1) \\`

`(a)/(-20) =(b)/(-4) =(c)/(1) \\d.r's~of ~reqd~line~is~-20,-4,1~or~20,4,-1`

now you find the point of intersection.

then calculate the angle.