Question

The voltage across a membrane forming a cell wall is 72.7 mV and the membrane is 9.22 nm thick. What is the magnitude of the electric field strength? (The value is surprisingly large, but correct.) You may assume a uniform E-field.

Answer 1

The magnitude of the electric field intensity is
`E = 7.89 *10^(6) \ V/m`

Step-by-step explanation:

From the question we are told that

The voltage is
`\epsilon = 72.7 \ mV = 72.7 *10^(-3) V`

The thickness of the membrane is
`t = 9.22 \ nm = 9.22 *10^(-9) \ m`

Generally the electric field intensity is mathematically represented as

`E = (\epsilon )/(t)`

substituting values

`E = (72.7 *10^(-3) )/(9.22 *10^(-9))`

`E = 7.89 *10^(6) \ V/m`